Load Transfer in Series and Parallel Paths by Kotur Raghavan
Recent articles were devoted for
understanding of load paths in structures. The topic was discussed in the
context of human body ( https://www.fembestpractices.com/2020/10/human-body-further-structural-insights.html
) and bicycle ( https://www.fembestpractices.com/2020/10/load-paths-in-structures-3-bicycle.html
). These two simple examples bring home
what is basically common to all structures. They are load application points
and reaction or support points. In a mathematical sense, they form the
extremities of any given structure which are connected to one another through
the load path. Structural analysis is concerned with study of the components which
occupy the load path.
Of special significance are the
members which are in series and those which are in parallel. By definition, the
same load passes through contiguous members which are in series. On the other
hand, members in parallel share load coming from a common contiguous member. In
the human body, the two legs share the load coming from the torso and hence they
are structural items in parallel. If the load is carried in the right hand the
same load passes through the palm, wrist, forearm and the arm. Those parts are
members in series. A weight placed on the head passes through the skull, neck
joint and the spinal column (consisting of 33 vertebrae located one upon other
and interlinked) on to the pelvic. Thus skull, neck joint and the spinal column
are in series. In a bicycle the two wheels can be considered to be members in
parallel. They share the loads coming from the central frame. The frame acts as
a single integral unit and does not contain clearly identifiable serial or
parallel members.
Schematically, structural
elements in series and parallel are represented using linear springs as shown
in the figure below.
Fig. 1
In the series arrangement, the same load will pass through K1 and K2 and each will stretch by lengths inversely proportional to stiffness. The deflection at the load application point is (F/K1+F/K2). In the parallel arrangement both K1 and K2 will stretch by equal lengths. The deflection at the load application point is (F/(K1+K2)). The force in K1 and K2 are (F*K1/(K1+K2)) and (F*K2/(K1+K2)) respectively. It is obvious that flexibilities get added in the case of series arrangement and stiffnesses get added in the case of parallel arrangement. For the two cases, the equivalent stiffness values are as stated below.
It can be recognised that the equivalent stiffness is governed more by the lower individual value in the series arrangement and by higher individual value in the parallel arrangement. Suppose that K1 is much greater than K2. Then the equivalent stiffnesses will be nearly equal to K2 and K1 in series and parallel arrangements respectively. The phrase ‘much greater than’ has certain amount of subjectivity. However, in engineering analysis a factor of 1000 or more can be deemed to be ‘much greater’.
The foregoing arguments are of
significance and can be exploited beneficially in developing optimum simulation
models. A few illustrations will help understand the approach.
1.
Cantilever
Beam with Spring Support
The cantilever
beam and the spring are structural elements in parallel. These are just
symbolic for the purpose of illustration and may represent something more
complex. The total stiffness at the tip can be seen to be (K + (3*E * I)/
L**3). If the spring stiffness is equal to the beam stiffness the load will be
equally shared between the beam and the spring. As the spring stiffness becomes
less and less its influence keeps on decreasing and the behaviour approaches
that of simple cantilever beam. The spring becomes practically ineffective when
the spring ratio is 0.001 or less. On the other hand, if the spring stiffness
is increased gradually it will dominate the beam. If the ratio is of the order
of 1000, the spring effectively becomes the reaction point and the beam will
hardly bend.
2.
Rotor
Bearing systems
In rotor
dynamics studies, modelling of the rotor-bearing systems normally pose some
challenge. The models are needed for critical speed and unbalance response
evaluations. A typical rotor-bearing system is shown in the figure below.
Fig. 3
Analysis models typically are as
shown in the figure below.
Three structural members are represented
by stiffnesses KR, KB and KH represent the rotor, bearing and housing
(pedestal) respectively. The rotor is in series with the support systems. The
two support systems, by themselves, are in parallel. MH is the housing mass.
Relative values of these stiffnesses are to be used as guideline for arriving
at the right model. Generally the rotor
happens to be the most flexible of the three. Bearing stiffnesses are generally
of comparable value in the case of oil film bearings and much higher in the case
of anti-friction bearings. Housing or pedestal stiffnesses are normally high.
As a result, frequently it happens that the analysis model shown below will be
adequate.
Models like this are very useful
for initial evaluation. They are also quite reliable for the first critical
speed which is dominated by flexure of the rotor.
3.
Slab
Column Assemblies
In the figure
below are shown typical constructional features in buildings.
Fig.
6
The slabs are
in flexure and the columns are in axial compression. The slab is in series with
the columns and columns, by themselves, are in parallel. As flexural stiffness
is normally low, quite often it will suffice to analyse only the slab by applying
constraints at column locations.
Key Takeaways
1. It
is a good practice to identify structural members which are in series and those
which are in parallel.
2. If
the members are in series, flexibilities add. In the case of parallel
arrangement stiffness values add.
3. The
value of ‘equivalent stiffness’ is governed by smaller value when they are in
series. Higher values govern equivalent stiffness when the members are in
parallel.
A prior knowledge of relative stiffness values will be helpful for arriving at simpler simulation models particularly in cases wherein stiffness ratios are of the order of 1000 or more.
PL**3/3EI is when the force is at the end. How about having the force at any other location or spring at any other location. ?
ReplyDeleteIt is an interesting question. This question came to my mind also.When the spring is located at the load application point the two components are in parallel in a well defined way. If the load is applied elsewhere the situation will be different. I will address this issue later.
DeleteThe first example problem is a borderline situation. Only when the load application point and the spring are at the same location it becomes parallel configuration. If the load is applied at any different location, the two supports together will happen to be in series with the beam. I will replace this case study with a more appropriate example.
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